Answer:
[tex]4.4\cdot 10^{11} kg m/s[/tex]
Explanation:
The relativistic momentum of an object is given by
[tex]p=\gamma m_0 v[/tex]
where:
[tex]\gamma = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}[/tex] is the relativistic factor, with v being the speed and c being the speed of light
m0 is the rest mass of the object
v is the speed
In this problem, we have
m = 1500 kg is the rest mass
v = 0.700 c is the speed of the meteorite
So we find
[tex]\gamma = \frac{1}{\sqrt{1-\frac{(0.700 c)^2}{c^2}}}=1.4[/tex]
And so the momentum is
[tex]p=(1.4)(1500 kg)(0.7\cdot 3\cdot 10^8 m/s)=4.4\cdot 10^{11}kg m/s[/tex]
