Answer:
0.041 mol.
Explanation:
- To solve this problem, we can use the general law of ideal gases:
PV = nRT,
where, P is the pressure of the air = 101 kPa = 0.9967 atm.
V is the volume of the air = 1.00 L.
n is the no. of moles of air = ??? mol.
R is the general gas constant = 0.082 L.atm/mol.K.
T is the temperature of the air = 23 °C + 273 = 296.0 K.
∴ n (no. of moles of air) = PV/RT = (0.9967 atm)(1.00 L)/(0.082 L.atm/mol.K)(296.0 K) = 0.041 mol.
