Step-by-step explanation:
[tex]x+3\sqrt{2x^{3}+8x^{2}+11x+4} \\\\2x^{3} /x=2x^{3-1} = 2x^{2} \\\\2x^{2}(x+3)=2x^{3} + 6x^{2}\\ \\subtract 2x^{2}+6x from2x^{2}+11+4=5x+4\\\\divide by divisor 5x/x=5x^{1-1} =5\\5(x+3)=5x+15\\subtract5x+15from 5x+4=-11\\remainder= 2x^{2} +2x+5\\answer= \frac{-11}{x+3}[/tex]
