Respuesta :

Blacklash

Answer:

 Option B is the correct answer.

Explanation:

 We have expression for sound intensity level,

                  [tex]L=10log_{10}\frac{I}{I_0}[/tex], where I is the intensity.

Here new intensity is given by 4I.

So, increase in  sound intensity level

        [tex]\delta L=10log_{10}\frac{4I}{I_0}-10log_{10}\frac{I}{I_0}=10log_{10}\frac{4I}{I}=6dB[/tex]

So, option B is the correct answer.

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