Answer is: C. CH3CHOHCH3.
Balanced chemical reaction of hydration of propene:
CH₃CH=CH₂ + H₂O → CH₃CHOHCH₃.
A hydroxyl group (OH⁻) attaches to one carbon of the double bond and a proton (H⁺) adds to the other carbon of the double bond according to Markovnikov's rule (hydrogen gets attached to the carbon with more hydrogen substituents).
Product of this reaction is propan-2-ol (isopropyl alcohol).
