ASSUMING BOTH VALUES ARE EQUAL
[tex] \frac{2}{ x} - \: 9 = x \\ \frac{2}{ x} = \: x + 9 \\ x = {x}^{2} + 9x \\ - 8x - {x}^{2} = 0 \\ - ( {x}^{2} + 8x) = 0 \\ x = 0 \: \: x = - 8[/tex]
ASSUMING THEY'RE NOT
[tex] \frac{2}{x} - 9 = k \\ \frac{2}{x} = k + 9 \\ 2 = (x) \times (k + 9) \\ 2 = (k \times x) +( 9 \times x)[/tex]
