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18-09-2018
Mathematics

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Openstudt what are the coordinates of the turning point for the function f(x) = (x − 2)3 + 1? (−2, −1) (−2, 1) (2, −1) (2, 1)

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Аноним Аноним

18-09-2018

f(x) = (x - 2)^3 + 1

Find the derivative:-

f'(x) = 3(x -2)^2 This = 0 at the turning points:-

so 3(x - 2)^2 =

giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1

Answer is (2, 1)

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