LucyMackin LucyMackin

20-05-2018
Mathematics

contestada

How do you find the x-intercepts of
[tex]y = 12x + {7x}^{2} [/tex]
Please help!!

Respuesta :

27-05-2018

x - intercepts → y = 0

[tex]y=12x+7x^2\to12x+7x^2=0\\\\x(12+7x)=0\iff x=0\ \vee\ 12+7x=0\\\\x=0\ \vee\ 7x=-12\\\\x=0\ \vee\ x=-\dfrac{12}{7}[/tex]

Answer: [tex]x=0;\ x=-\dfrac{12}{7}[/tex]

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