Suppose 6 quarts of a solution that is 45% antifreeze is mixed with 2 quarts of a solution that is 19% antifreeze.

Respuesta :

6+2=8 quarts of a new solution

0.45*6  - quarts  antifreeze in a solution that is 45% antifreeze
0.19*2  - 
quarts  antifreeze in a solution that is 19% antifreeze

x- concentration of a new solution
8x -  quarts  antifreeze in a new solution 

0.45*6 + 0.19*2 = 8x
3.08=8x
x= 0.385 =38.5 %