sabriar04 sabriar04

18-09-2022
Mathematics

contestada

In triangle AABC, ZC is a right angle and CD is the altitude to AB . Find
the angles in ACBD and ACAD if
mZA = 20°
m/DBC = 70°
m/DCB=
m/CDB = 90°
m2 ACD=70°
m/ADC = 90°

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